1+8+0 = 9
or
180+80+0 = 260
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The sum is 3*(x-1) or 3x - 3
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
-4, -2, 0, and 2 are the four consecutive even integers. When you add them up they equal -4.
Let's see if this is true. Assume that their sum is 48. So, x + (x +1) + (x + 2) = 48 3x + 3 = 48 Subtract 3 at both sides; 3x = 45 Divide 3 to both sides; x = 15 x + 1 = 15 + 1 = 16 x + 2 = 15 + 2 = 17 So, 15 + 16 + 17 = 48 Answer: The sum of three consecutive integers such as 15, 16, and 17 is 48.
Integers are n, n + 1 and n + 2, so 3n + 3 = 13 + 2n Subtract 2n from each side: n + 3 = 13 Subtract 3 from each side: n = 10 Job done.