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Any 3 digit number that ends with a "0."

100, 110, 120 and 130.

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Q: What are four 3 digit numbers that are divisible by 10?
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Related questions

What one digit numbers are divisible by ten?

No one-digit numbers are divisible by 10. 10 is divisible by 1, 2 and 5.


How many 3-digit numbers are divisible by 13?

-10


How many 2 digit numbers are divisible by 5?

There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.


How many six digit numbers that is numbers between 100000 and 999999 are divisible by 10?

There are 90,000 such numbers.


How many 6 digits numbers can be formed from the digit 01357 and 9 which are divisible by 10 and no digit is repeated?

There are 5! = 120 such numbers.


Which of the following is a four digit number divisible by both 5 and 10?

1,234


How many two digit numbers divisible by neither 3 nor 5?

48.The first two digit number is 10, the last two digit number is 99, so there are 99 - 10 + 1 = 90 two digit numbers→ 10 ÷ 3 = 31/3 → first two digit number divisible by 3 is 4 x 3 = 12→ 99 ÷ 3 = 33 → last two digit number divisible by 3 is 33 x 3 = 99→ 33 - 4 + 1 = 30 two digit numbers divisible by 3→ 10 ÷ 5 = 2 → first two digit number divisible by 5 is 2 x 5 = 10→ 99 ÷ 5 = 194/5 → last two digit number divisible by 5 is 19 x 5 = 95→ 19 - 2 + 1 = 18 two digit numbers divisible by 5→ 30 + 18 = 48 two digit numbers divisible by 3 or 5 OR BOTH.The numbers divisible by both are multiples of their lowest common multiple: lcm(3, 5) = 15, and have been counted twice, so need to be subtracted from the total→ 10 ÷ 15 = 010/15 → first two digit number divisible by 15 is 1 x 15 = 15→ 99 ÷ 15 = 69/15 → last two digit number divisible by 15 is 6 x 15 = 90→ 6 - 1 + 1 = 6 two digit numbers divisible by 15 (the lcm of 3 and 5)→ 48 - 6 = 42 two digit numbers divisible by 3 or 5.→ 90 - 42 = 48 two digit numbers divisible by neither 3 nor 5.


What are the divisibility rules for 1 2 3 4 5 6 9 and 10?

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.


4-digit number divisible by 5 and 10?

Any number whose last digit is 0 would be divisible by both these numbers. 1000, 1010, 1020...


What is a four digit number that can be divisible by 9 and 10?

9000 / 9 = 1000 9000 / 10 = 900


What 3 digit numbers are evenly divisible by 3 and 10?

120, 150, 180,210,240,270,300,330,60,390,420,450, 480,510,540,570,600,630,660,690,720,750,780,810,840,870,900,930,860,990


What is a 4 digit number that is divisible by 5 an 10?

The first four digit number is 1,000 So 1000 / 5 = 200 and 1000 /10 = 100