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An experiment with only two outcomes ("success" and "failure"), a constant probability of success, a number of independent trials. Then, if the probability of a success in a trial is p, the probability of r successes in n trials is nCr*pr*(1-p)(n-r) for r = 0, 1, 2, ..., n. In case the super-and sub-scripts do not work, that is n!/[r!*(n-r)!]*p^r*(1-p)^(n-r)
n+n-n-n-n+n-n-n squared to the 934892547857284579275348975297384579th power times 567896578239657824623786587346378 minus 36757544.545278789789375894789572356757583775389=n solve for n! the answer is 42
n2 + n = n(n + 1)
n^2 + n
N+n=0