(3x - 1)(x - 4) so roots are 1/3 and 4
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
No. It would not be a polynomial function then.
Roots of a polynomial that can be written in the form p/q are called _____ roots. Rational ;)
Rational roots
here is the graph
It can have 1, 2 or 3 unique roots.
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
(3x - 1)(x - 4) so roots are 1/3 and 4
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
TRue
No. It would not be a polynomial function then.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
x^2+2x+1
Roots of a polynomial that can be written in the form p/q are called _____ roots. Rational ;)
A third degree polynomial could have one or three real roots.