here is the graph
It can have 1, 2 or 3 unique roots.
A fifth-degree polynomial function will have exactly five roots, counting multiplicities. This means that some of the roots may be repeated or complex, but the total number of roots, including these repetitions, will always equal five. If the polynomial has real coefficients, some of the roots may also be non-real complex numbers, which occur in conjugate pairs.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
A third degree polynomial could have one or three real roots.
4, the same as the degree of the polynomial.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
Each distinct real root is an x-intercept. So the answer is 4.
Four.Four.Four.Four.
1
5, Using complex numbers you will always get 5 roots.
To find the roots of the polynomial (3x^5 + 2x^3 + 3x), we can factor out the common term, which is (x): [ x(3x^4 + 2x^2 + 3) = 0. ] This shows that (x = 0) is one root. The quartic polynomial (3x^4 + 2x^2 + 3) does not have real roots (as its discriminant is negative), meaning it contributes no additional real roots. Therefore, the polynomial has only one real root, which is (x = 0).