is 28x squared? if it is, the answer would be, 3(2x+5)(4x+3).
The "solution" means the numerical values of 'x' and 'y' that make the statement true.Right now, there are an infinite number of solutions. Here are a few of them:X . . . . Y-1 . . . . 22 . . . . . 45 . . . . . 68 . . . . . 811 . . . . 10In general, you need the same number of separate equations as the number of "variables"or "unknowns" in them.Since your equation has two unknowns ... 'x' and 'y' ... you need another equation, in order topin the solution down to a single pair of numbers for them.
x = -6
-6x+9 = 45 -6x = 45-9 -6x = 36 x = -6
Linear algebraic inequalities can be described as an expression with a variable >/< an expression with a variable. For example, 2x<90 so x<45. Inequalities don't yield a particular solution, but rather solution sets. In the above example, x<45, means that the solution set is all of the values less than 45.
The solution to the problem -10-2x-45 is 80 from the simplified form (90-10).
45 + x + 54 + x 2x + 99
18x + 45 or 9(2x + 5) how is this answer figured?
This website isn't equipped to reproduce most mathematical symbols in the questions. I'll see if I can translate. 2x + 3(x - 10) = 45 2x + 3x - 30 = 45 5x - 30 = 45 5x = 75 x = 15 Check it. 2(15) + 3(15 - 10) = 45 30 + 15 = 45 It checks.
9(2x + 5)
It is an algebraic expression.
There are several equations that can equal 57. 45 plus 12 is equal to 57, as is 30 plus 27.
First of all add all common factors. In par. (2x) + 15 + (2x) = 180 4x + 15 = 180 Divide 4x and 180 by 4. (4x/4) + 15 = (180/4) x + 15 = 45 Then subtract 15 to 15 and 45. x + (15-15) = (45-15) x = 30 Answer is X = 30.
The answer is 20+25=45
is 28x squared? if it is, the answer would be, 3(2x+5)(4x+3).
The "solution" means the numerical values of 'x' and 'y' that make the statement true.Right now, there are an infinite number of solutions. Here are a few of them:X . . . . Y-1 . . . . 22 . . . . . 45 . . . . . 68 . . . . . 811 . . . . 10In general, you need the same number of separate equations as the number of "variables"or "unknowns" in them.Since your equation has two unknowns ... 'x' and 'y' ... you need another equation, in order topin the solution down to a single pair of numbers for them.
There is no equation in the question, only an expression. An expression cannot have a solution.