There is no equation in the question, only an expression. An expression cannot have a solution.
what the solution to this equation x+15=28 If you mean: x+15 = 28 then the value of x works out as 13
3m + 15 = 45 3m = 30 m = 10
An equation for 15 and 10 could be written as: 15 = 10 + x, where x is the difference between 15 and 10. In this case, x would equal 5, as 15 is 5 more than 10. Another way to represent this equation is: 15 - 10 = x, which simplifies to 5 = x. Therefore, the equation for 15 and 10 is 15 = 10 + 5 or 15 - 10 = 5.
18 + 10 + 20 + 30 + 15 + 50= 143
The answer to the equation 80 times 3 Y plus 2 Y plus 4 plus 1 equals -15. This is considered to be a math problem.
-5
-15 + x100 is an expression, not an equation nor inequality. There is, therefore, no solution.-15 + x100 is an expression, not an equation nor inequality. There is, therefore, no solution.-15 + x100 is an expression, not an equation nor inequality. There is, therefore, no solution.-15 + x100 is an expression, not an equation nor inequality. There is, therefore, no solution.
Without an indication of the equals sign, this is not an equation.
what the solution to this equation x+15=28 If you mean: x+15 = 28 then the value of x works out as 13
If: 4x = x+15 Then: x = 5
The equation ( x + (-5) - 10 ) simplifies to ( x - 5 - 10 ), which can be further simplified to ( x - 15 ). Therefore, the simplified form of the equation is ( x - 15 ).
The value of x in the equation -10+4x = 50 is 15
3m + 15 = 45 3m = 30 m = 10
If: 11x+25 = 7x+15 then there is only one solution and it is x = -2.5
It is not an equation because there's no equal sign but it is an expression that can be simplified to: 17y-10
Without an equality sign the given terms can't be considered to be an equation and so therefore there is no solution.
To determine if (-15) is a solution to the equation (y - 3x^2 - 8x = 0), we need to substitute (y = -15) into the equation. This gives us (-15 - 3x^2 - 8x = 0). For (-15) to be a solution, there must be corresponding values of (x) that satisfy the equation. However, without specific values for (x), we cannot conclude that (-15) is a solution.