Perhaps you mean words with an x? axe, ox, sex, extreme, extra, extract, six.
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Since all the letters are different, the answer is 7! = 1 x 2 x 3 x 4 x 5 x 6 x 7.
If all the letters are unique in the set, there are 6 choices for the first letter, 5 for the second letter, 4 for the third letter, etc. This results in 6 X 5 X 4 X 3 X 2 = 720 arrangements. If some of the six letters are duplicated, there will be fewer distinct arrangements.
Assuming that you have to use all 4 of the letters with no repeats there are 4! or 4 factorial. Because you are asking how many ways can I arrange n objects if I use all n of them, the number of permutations is n!. To calculate factorials, you multiply the number by every integer before it until you reach 1. So 4! equals 4 X 3 X 2 X1 or 24. So there are 24 ways you can arrange the letters G,X,K, and T.
6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 ways
4 possibilities for the first letter to choose from S O C K.Then there are 3 letters to choose from for the second letter.Then there are 2 letters left to choose from for the third letter.Then there will be only 1 remaining letter left for the last of the four positions.So: We have 3 possibilities for the second letter for a total of 4 x 3 = 12 combinations.With 2 possibilities for the third letter we get 12 x 2 or 4 x 3 x 2 = 24 possibilities.Since there is only one letter left for the fourth position, it still is 4 x 3 x 2 x 1= 24 possibilities.In mathematics we abbreviate 4 x 3 x 2 x 1 to 4! (4 followed by an exclamation mark) and call it 4 factorial.