Yes I can. = v-16-4v = -4v-2 = you have to move all the variables to one side, and all the numbers to the other side... v - 4v + 4v = 16 -2 v= 14
it equals 3+4v
Step 1. Divide by 4v: 4v(3v2 + v - 24) Step 2. 4v(3v - 8)(v + 3)
12+ 4v = 25 subract 12 from each side of the '=' sign. 4v = 13 divide each side by 4 v= 3.25 thus: 12+ (4x3.25) = 25
260
The answer is -4v + 83v^2.
Yes I can. = v-16-4v = -4v-2 = you have to move all the variables to one side, and all the numbers to the other side... v - 4v + 4v = 16 -2 v= 14
it equals 3+4v
It is equal to: 20v^2 +4v -24
Solve S = 4v2 for v . -4(4-v)= -2(2v-1) v-16+4v = -2(2v-1) v-16+4v = -4v + 2 -16+5v = -4v + 2 5v = -4v + 18 9v = 18 v = 2
-8-3v = 4v+48 -3v-4v = 48+8 -7v = 56 v = -8
Step 1. Divide by 4v: 4v(3v2 + v - 24) Step 2. 4v(3v - 8)(v + 3)
In older cars 4v = a four barrel carburetor. 2v would be a two barrel and a 1v would be one barrel
12+ 4v = 25 subract 12 from each side of the '=' sign. 4v = 13 divide each side by 4 v= 3.25 thus: 12+ (4x3.25) = 25
Yes it did
kmnh
1967 Mustang specs:Available Engines:200cid 6cyl 1V 120hp289cid 2V V-8 200hp289cid 4V V-8 225hp289cid 4V V-8 271hp390cid 4V V-8 320hp