Let the five consecutive numbers be (x, x+1, x+2, x+3, x+4). The sum can be expressed as (5x + 10 = 110). Solving for (x), we find (5x = 100), giving (x = 20). Therefore, the five consecutive numbers are 20, 21, 22, 23, and 24.
The numbers are 54 and 56.
The numbers are 110, 111 and 112.
110
The numbers are 110 & 111.These are consecutive because when we count 111 comes immediately after 110. 110 is less than 110.8 (by 0.8) and 111 is greater (by 0.2).
The pair of consecutive palindromic mileages after 10001 that are 110 miles apart is 10201 and 10311. Both numbers are palindromes, meaning they read the same forwards and backwards. 10201 + 110 equals 10311, confirming the required difference.
The numbers are 54 and 56.
The numbers are 110, 111 and 112.
110
The numbers are 110 & 111.These are consecutive because when we count 111 comes immediately after 110. 110 is less than 110.8 (by 0.8) and 111 is greater (by 0.2).
The whole consecutive numbers that 110 lies between are 109 and 111. In mathematics, when we say a number lies between two other numbers, we mean that it is greater than the lower number and less than the higher number. In this case, 110 is greater than 109 and less than 111, making it lie between these two consecutive numbers.
The LCM of any two consecutive numbers greater than zero is the two numbers multiplied together. eg. the LCM of 10 and 11 is: 10*11=110
10 and 11
560
560
108 109 110 111 112 113 114
The pair of consecutive palindromic mileages after 10001 that are 110 miles apart is 10201 and 10311. Both numbers are palindromes, meaning they read the same forwards and backwards. 10201 + 110 equals 10311, confirming the required difference.
110, 111 and 112. The middle one must be a third of the total.