Basically 1, 2, 3, 4, 5 are all real numbers, but as a real number doesn't only limit of integers, it can be 2/5, √2, or even π.
0 is a real number.
The question is confusing. The additive inverse of a real number is the same number with the sign changed. For example, the additive inverse of -5 is +5 (or simply 5); the additive inverse of 7 (which is the same as +7) is -7.
No. The square root of negative one is an example of an imaginary (not real) number. Pi is irrational, but real.
2 is a real world prime number.
It need not be. For example, a complex number as a percent of most other complex numbers, or any real number, will not be a real number.
1/2, 5, pi, respectively
0 is a real number.
The question is confusing. The additive inverse of a real number is the same number with the sign changed. For example, the additive inverse of -5 is +5 (or simply 5); the additive inverse of 7 (which is the same as +7) is -7.
No. The square root of negative one is an example of an imaginary (not real) number. Pi is irrational, but real.
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2 is a real world prime number.
Real
Yes, Any real number squared is a real number. In this case that number is 25.
It need not be. For example, a complex number as a percent of most other complex numbers, or any real number, will not be a real number.
Any real number (besides zero) divided by itself is equal to 1. In algebraic terms, if x is a non-zero real number then x/x=1. Zero is the exception because dividing a number by zero is undefined. For example 5 divided by itself is 1. 5/5=1
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
3 and 5 are both complex numbers, and if you multiply them together, you get 15, which is a real number. If you were looking for two non-real complex numbers, then any pair of complex conjugates will work. For example, 5+2i times 5-2i is 29.