47, 40, 33, 26, 19, 12, and 5
Assume this is an arithmetic sequence (It is formed by continually adding or subtracting the same number.)
Because there are 7 missing numbers, there must have been 8 subtractions (the last one will produce the -2). The difference between the first and last terms is 54-(-2) = 54+2 = 56. Divide this by 8; the amount subtracted each time is 7. The missing numbers are 54-7 = 47, 47-7 = 40, ...
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The missing number is 26. The number after 29 is 58.
It is (5+37)/2 = 21.
The missing number in this sequence is 64, or 4 raised to the third power. You find the answer by noting that each number in the sequence is a counting number starting at 1 that is raised to the third power. For example, 2 raised to the third power (2 x 2 x 2) is 8.
There does not appear to be a missing number. The sequence is n2 + 1. 12 + 1 = 2 : 22 + 1 = 5 : 52 + 1 = 26 : 262 + 1 = 677. The next number in the sequence is 6772 + 1 = 458330.
9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))