47, 40, 33, 26, 19, 12, and 5
Assume this is an arithmetic sequence (It is formed by continually adding or subtracting the same number.)
Because there are 7 missing numbers, there must have been 8 subtractions (the last one will produce the -2). The difference between the first and last terms is 54-(-2) = 54+2 = 56. Divide this by 8; the amount subtracted each time is 7. The missing numbers are 54-7 = 47, 47-7 = 40, ...
The missing number is 26. The number after 29 is 58.
It is (5+37)/2 = 21.
The missing number in this sequence is 64, or 4 raised to the third power. You find the answer by noting that each number in the sequence is a counting number starting at 1 that is raised to the third power. For example, 2 raised to the third power (2 x 2 x 2) is 8.
There does not appear to be a missing number. The sequence is n2 + 1. 12 + 1 = 2 : 22 + 1 = 5 : 52 + 1 = 26 : 262 + 1 = 677. The next number in the sequence is 6772 + 1 = 458330.
9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))
The missing number is 26. The number after 29 is 58.
178 is the answer By using the formula a{n} = n³ + n² + 5n + 3 For e.g. A{2} =2 ³ +2²+5*2+3=25 =8+4+10+3=25 And so on.    = 10, 25, 54, 103, 178
256 (each number is the square of the preceding number)
It is (5+37)/2 = 21.
The pattern looks like the previous number is multiplied by -3, hence the next number in the sequence would be (-54) x (-3) = 162
The missing number in this sequence is 64, or 4 raised to the third power. You find the answer by noting that each number in the sequence is a counting number starting at 1 that is raised to the third power. For example, 2 raised to the third power (2 x 2 x 2) is 8.
Dodging numbers may be missing numbers in a sequence. For example, the underscore in the following sequence represents such a number: 2, 4, _ , 8, 10.
The missing number is 5. They're the first five prime numbers.
The sequence is 1,2,3,5,8,13,21.......8 is the missing number. This is known as a Fibonacci Sequence. The first two numbers are supplied and then further numbers in the sequence are formed from the sum of the two prior numbers. 3 = 1 + 2 5 = 2 + 3 8 = 3 + 5.....and so on.
There does not appear to be a missing number. The sequence is n2 + 1. 12 + 1 = 2 : 22 + 1 = 5 : 52 + 1 = 26 : 262 + 1 = 677. The next number in the sequence is 6772 + 1 = 458330.
9, 81, 6561, 43046721, ...This would be the sequence 9^(2^(n-1))
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