The sum of the exterior angles of a polygon is 360°.
There are the same number of exterior angles as there are sides.
For a regular polygon all the angles are the same size:
→ number_of_sides × exterior_angle = 360°
→ exterior_angle = 360° ÷ number_of_sides
→ exterior_angle = 360° ÷ 5 = 72°
Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.
thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees
Exterior angle = 14.4 degrees Interior angle = 165.6 degrees
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
162 degrees
Exterior angle = 360/Number of sides = 360/5 = 72 degrees. Interior angle = 180 - Exterior angle = 180 - 72 = 108 degrees.
Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!
108'
thirty sixImproved Answer:-Providing that it's a regular pentagon then each interior angle will measure 108 degrees
Each exterior angle is 360/6 = 60 degrees
135 degrees and its exterior angle is 45 degrees
Exterior angles are supplementary with interior angles, so 180-30=150
Exterior angle = 14.4 degrees Interior angle = 165.6 degrees
exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°
To the nearest tenth, the interior angle of a regular pentagon is 108.0o In a regular pentagon, the sum of the interior angles is (5 - 2) x 1800 = 3 x 1800 = 540o In a regular pentagon, the interior angles are all the same size and are 5400 ÷ 5 = 108o which to the nearest tenth is 108.0o
Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees
162 degrees