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b+b+b+c+c+c+c =3b+4c
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
C plus is between 3 and 3.2. C = 75% 0% < Plus < 5% 75%+0% < C Plus < 75%+5% 75 < C Plus < 80% 75%*4 < C Plus < 80% * 4 (3/4)*4 < C Plus < (4/5) * 4 3 < C Plus < 16/5 3 < C Plus < 3.2
2b + 2c or 2(b + c)
It is c + 12.