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According to the Boolean algebra 1 plus A plus B plus C is equal to?
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
What is b plus b plus b plus c plus c plus c plus c?
b+b+b+c+c+c+c =3b+4c
Would you Prove If a equals b and c d then a plus c b plus d?
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
What do a and b and c and d represent if a plus a and b plus a and b and c plus a and b and c and d equals 2006?
And how does this relate to coins?
If a plus b equals c what does a plus c equal?
A+c= 2a+b
According to the Boolean algebra 1 plus A plus B plus C is equal to?
1. With boolean algebra, 1 + n is always equal to 1, no matter what the value of n is.
What is c plus C plus C answer in algebra?
3c
What is b plus b plus b plus c plus c plus c plus c?
b+b+b+c+c+c+c =3b+4c
B plus b plus b plus c plus c plus c plus c equals?
b + b + b + c + c + c + c = 3b + 4c
Would you Prove If a equals b and c d then a plus c b plus d?
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
What is the definition of pre-algebra?
If a=b and b=c then a must = c
What is the answer for algebra abc plus ab?
You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )
What is B plus B plus B plus C plus C plus C?
It is impossible to give any decimal/numeric value if we are not given the values of at least one variable, so the answer is B + B + B + C + C + C.
What is 2b-2c in algebra?
2(b - c)
What do a and b and c and d represent if a plus a and b plus a and b and c plus a and b and c and d equals 2006?
And how does this relate to coins?
How would you simplify the boolean algebra expression a'bc plus ab'c plus abc' plus abc?
ab'c + abc' + abc = a(b'c + bc' + bc) = a(b'c + b(c' + c)) = a(b'c + b) = a(c + b) I'm not sure if there's a proper name for that last step, or multiple steps to get to it, but it is intuitively correct. b + b'c is equivalent to b + c. Here's a quick truth table to show it: bcb'b'cb'c+bb+c0010000111111000111100 11
If a plus a equals b and b plus c equals a and a-c equals b what is c?
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
