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The coefficients in the expansion of ((x + y)^4) can be found using the binomial theorem, which states that ((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k). For ((x + y)^4), the coefficients are given by (\binom{4}{k}) for (k = 0, 1, 2, 3, 4). This results in the coefficients: 1, 4, 6, 4, and 1. Therefore, the full expansion is (x^4 + 4x^3y + 6x^2y^2 + 4xy^3 + y^4).
What else can I help you with?
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
What is the answer to 2x equals y4?
x=y4 /2
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
The coefficients in the expansion of (x plus y)4 are?
1,4,6,4,1
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
(4x-y) plus (-10 plus y) if x3 and y4?
If x = 3 and y = 4 then the answer is 2
What is the answer to 2x equals y4?
x=y4 /2
Determine the value of 2x plus 3xy plus 4y when x-2 and y4.?
4 + 24 + 16 = 44
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
What are the factors of x2 - y4?
-2
How do you express x4 plus y4 if given x plus y equals a xy equals b?
(x + y)2 = x2 + 2xy + y2 So x2 + y2 = (x + y)2 - 2xy = a2 - 2b Then (x2 + y2)2 = x4 + 2x2y2 + y4 So x4 + y4 = (x2 + y2)2 - 2x2y2 = (a2 - 2b)2 - 2b2 = a4 - 4a2b + 4b2 - 2b2 = a4 - 4a2b + 2b2
How is the pascal triangle and the binomial expansion related?
If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.
