Length 1 and Width 17
Length 2 and Width 16
Length 3 and Width 15
Length 4 and Width 14
etc..... get the picture
The perimeter of a rectangle is the sum of its 4 sides added together.
me
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
The perimeter of a rectangle is always even because the perimeter is twice the length plus twice the width. Whenever you multiply a number by 2, the product is even. When you add two even numbers the sum is even.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
The perimeter of a rectangle is the sum of its 4 sides added together.
In whole numbers, the greatest perimeter would be a rectangle 48 x 1, resulting in a perimeter of 98m.
me
You must first calculate the width, using the formula for the area of a rectangle (plug in the numbers you know into the formula, and solve for width). Once you know this, you can plug in the numbers in the formula for a rectangle's perimeter.
In order to know the perimeter of a rectangle, you need to know both its length and its width ... two numbers. One number isn't enough. If one side of a rectangle is 22 feet, then the perimeter of the rectangle can be any number greater than 44 feet. There are an infinite number of different possibilities.
Any number between 0 and 12 that you like. There is no need for the sides of the rectangle to be whole numbers!
The perimeter of a rectangle is always even because the perimeter is twice the length plus twice the width. Whenever you multiply a number by 2, the product is even. When you add two even numbers the sum is even.
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
Simple the Perimeter you just add the outside numbers. For area. When I look at an octagon I see a rectangle and two Trapezoids on either side of the rectangle. So find the area of each object then add the areas up and voila you got the area of a rectangle.
The way the rectangle is usually defined, a rectangle has to be positive, so any number greater than zero will do. Note that the set of numbers greater than zero has no minimum.
If it was a square, the answer would be 81 square cm. The area will be the product of two numbers whose sum is half the perimeter.
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2