0
I think this means what digit appears in the units column (the right-most) when you multiply a number by 5. If the original number was even (divisible exactly by 2) the right-most digit will be "0". If odd, it will be "5". Examples 30 x 5 = 150, and 31 x 5 =155. If there are places to the right of the decimal point, you could get anything, example 31.6 x 5 = 158.0
What else can I help you with?
Multiply 123456789 by a 1 digit number other than 1 to get a product containing each of the nine digits once and only once?
8
What is the partial product for 315 x 4?
To find the partial product for 315 x 4, you multiply each digit of 315 by 4 separately. Starting with the rightmost digit, you get 5 x 4 = 20. Next, you move to the middle digit, 1, and get 1 x 4 = 4. Finally, you multiply the leftmost digit, 3, by 4 to get 12. Combining these results, you get the partial products 120, 60, and 4, which sum up to 484.
Use the digit 1234 and 5 to form a two digit and three digit number so their product is the least product possible use each digit once?
123, three number 45, two number
How do you work out 143 x 37?
143x37----1001 First you multiply the 7 by each digit in 1 4 3, carrying over tens digits.429 Then moving over to left 1 place, multiply 3 by 143.5291 Then add the two numbers in the columns. Answer = 5291
Find 5 four digit numbers such that the product of the digits of each four digit prime number are also prime?
You had me until "product." The product of 4 digits can't be prime.
How do you multiply by two-digit numbers?
To multiply two digit numbers, multiply each place value of a factor by each place value digit and add the results.
If there is partial quotient then there must be partial product. If there is partial product, how do you do it?
In division, the partial quotient method involves breaking down the dividend into smaller, more manageable parts to simplify the division process. The partial product method, on the other hand, is commonly used in multiplication and involves multiplying each digit in one number by each digit in the other number and then adding the results. To perform the partial product method, you would multiply each digit of the multiplicand by each digit of the multiplier, starting from the rightmost digit and moving leftwards, and then summing up the products to get the final result.
Multiply 123456789 by a 1 digit number other than 1 to get a product containing each of the nine digits once and only once?
8
Explain why second partial product is always greater than the first partial priduct when you multiply two 2-digit numbers?
The product of two digit numbers is always greater than either.
How does the place of each digit help the value of the number?
the place of each digit help the value of the number by using your multuplication
Estimate the product of 77 and 33?
When estimating, you round each of the terms. When the ones-place digit is greater than five, the tens-place digit rounds up. Because 77 is greater than 75, it rounds up to 80. And because 33 is less than 35, it rounds to 30. So, to estimate the product of 77 and 33, you multiply 80 and 30. 80 x 30 = 240. Therefore, the answer is 240.
How do you multiply 313 times 3?
In this case you can take each digit and multiply it by 3, to give 939.
What is the partial product for 315 x 4?
To find the partial product for 315 x 4, you multiply each digit of 315 by 4 separately. Starting with the rightmost digit, you get 5 x 4 = 20. Next, you move to the middle digit, 1, and get 1 x 4 = 4. Finally, you multiply the leftmost digit, 3, by 4 to get 12. Combining these results, you get the partial products 120, 60, and 4, which sum up to 484.
How did you find each of the products?
You multiply together the components of each product.
Use the digit 1234 and 5 to form a two digit and three digit number so their product is the least product possible use each digit once?
123, three number 45, two number
How do you work out 143 x 37?
143x37----1001 First you multiply the 7 by each digit in 1 4 3, carrying over tens digits.429 Then moving over to left 1 place, multiply 3 by 143.5291 Then add the two numbers in the columns. Answer = 5291
Find 5 four digit numbers such that the product of the digits of each four digit prime number are also prime?
You had me until "product." The product of 4 digits can't be prime.
