To find the partial product for 315 x 4, you multiply each digit of 315 by 4 separately. Starting with the rightmost digit, you get 5 x 4 = 20. Next, you move to the middle digit, 1, and get 1 x 4 = 4. Finally, you multiply the leftmost digit, 3, by 4 to get 12. Combining these results, you get the partial products 120, 60, and 4, which sum up to 484.
10 x 4 = 4 4 x 4 = 16 40 + 16 = 56 14 x 4 = 56
315
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
4 x 40 = 160 4 x 8 = 32 160 + 32 = 192 4 x 48 = 192
200 x 80 = 16000 10 x 80 = 800 200 x 4 = 800 10 x 4 = 40
10 x 4 = 4 4 x 4 = 16 40 + 16 = 56 14 x 4 = 56
34 x 28 = 34 x (20 + 8) First partial product is: (30 + 4) x 8 = 240 + 32 Second partial product is: (30 + 4) x 20 = 600 + 80 Sum of partial products = total product = 600 + 240 + 80 + 32 = 952
315
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
4 x 40 = 160 4 x 8 = 32 160 + 32 = 192 4 x 48 = 192
4 x 20 = 80 4 x 7 = 28 80 + 28 = 108 4 x 27 = 108
200 x 80 = 16000 10 x 80 = 800 200 x 4 = 800 10 x 4 = 40
Multiply them.3 x 3 x 5 x 7 = 315
x+(x+2)+(x+4)+(x+6)+(x+8) = 315 5x+20 = 315 5x = 315-20 5x = 295 x = 59 Therefore, if x = 59, x+2 = 61, x+4 = 63, x+6 = 65, x+8 = 67. The answers are 59, 61,63, 65 and 67
5, 7, 95 + 7 + 9 = 215 x 7 x 9 = 315
Single digits don't have partial products. 8 x 6 = 48
the way of partial products for the problem 34 x 64= 34 65 30 x 60 = 1,800 30 x 5 = 150 4 x 60= 240 4 x 5= 20then add all the numbers 1800+150+240+20= 2,210 answer 2,210