The area of a rectangle does not provide enough information.
Let L be any number greater than sqrt(60) = approx 7.75 and let B = 60/L.
Then a rectangle with length L units and Breadth B units will have an area of L*B = L*(60/L) = 60 square units. Since L can be any number greater than 7.75, there are infiitely many choices for L and so infinitely many possible rectangles.
The dimensions are 4 units by 15 units
It is not possible to answer the question because you have not provided the measurement units for 60 and 120: micrometres, inches, miles?
Assuming that the "5 and 12" refer to side lengths, the answer is 5*12 = 60 square units.
15 X 4 = 60 square units of whatever unit the length measurements are.
The dimensions of the rectangle are 21 units by 9 units
The dimensions are 4 units by 15 units
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
It is not possible to answer the question because you have not provided the measurement units for 60 and 120: micrometres, inches, miles?
The diagonal is 100'
Assuming that the "5 and 12" refer to side lengths, the answer is 5*12 = 60 square units.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
15 X 4 = 60 square units of whatever unit the length measurements are.
The dimensions of the rectangle are 21 units by 9 units
rectangle with 10" length and 2x-4 width 60" area
The length is 20 units and the width is 10 units
As stated in the question, it is a field with an area of 60 square units. Nothing more, nothing less!
60 square feet is an area equal to that of a ten-foot by six-foot rectangle.