if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle?
Use Pythagoras' theorem to find the length of the rectangle which will be 12
5*12 = 60 square units
Multiply the length and width to find the area of both a rectangle and square.
length times width
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².
By the Pythagorean Theorem, the diagonal is the hypotenuse of the right triangle formed by the diagonal and the two included sides. c2 = a2 + b2 so the diagonal is the square root of the sum of the squares of the rectangle's length and width. Example : for a rectangle 4 x 3, the diagonal is sqrt(32 + 42) = sqrt (25) = 5
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. In this case, the diagonal forms the hypotenuse of a right triangle with the sides being the length and width of the rectangle. So, the diagonal (d) can be calculated as d = √(4^2 + 6^2) = √(16 + 36) = √52 ≈ 7.21 feet.
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
Suppose the width is W and the diagonal is D.Then, by Pythagoras's theorem, the length, L, is given by L = sqrt(D^2 - W^2).And then, area = L*W.
The diagonal is 3.61cm
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
infinitely far