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What is the perimeter of 26 and 16?
If they are the dimensions of a rectangle then the perimeter is: 2*(26+16) = 84
The radius of the semicircle is 5 feet and the dimensions of the rectangle are 10 ft by 16 ft The semicircle is attached to the width of it What is the perimeter?
Perimeter = (2*pi*5*1/2)+10+16+16 = 57.70796327 or 58 feet
What happens to the perimeter of a rectangle when its length and width are quadrupled?
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
The perimeter of a rectangle is 48 feet If the length measures 16 feet what is the width?
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
What are the dimensions of a rectangle that has a perimeter of 16 cm and an area of 15.75 square cm?
The dimensions are: 3.5 cm and 4.5 cm Check: perimeter = 3.5+4.5+3.5+4.5 = 16 cm and area = 3.5*4.5 = 15.75 cm2
What is the perimeter of 26 and 16?
If they are the dimensions of a rectangle then the perimeter is: 2*(26+16) = 84
The radius of the semicircle is 5 feet and the dimensions of the rectangle are 10 ft by 16 ft The semicircle is attached to the width of it What is the perimeter?
Perimeter = (2*pi*5*1/2)+10+16+16 = 57.70796327 or 58 feet
What is the perimeter of a rectangle that is 9 feet by 16 feet?
It is 9+16+9+16 = 50 feet
What are the dimensions of a rectangle if the preimeter is 16 feet and the area is 12 feet?
A 6 by 2 feet rectangle
What is the perimeter of a rectangle with a diagonal length of 7 feet and an area of 16 feet squared?
The perimeter is 18 feet.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
What is the perimeter and the area of a rectangle that is 12 feet x 16 feet?
A rectangle has 2 pairs of equal sides. perimeter is the sum of the lengths of all sides: Perimeter = 12 + 12 + 16 + 16 = 56 Ft Area = 12 x 16 = 192 Ft2
What is the perimeter of 5 yards and the width of 3 yards?
If those are the dimensions of a rectangle then its perimeter is 2*(5+3)=16 yards
How do you solve the problem Nu is disigning a rectangular sandbox The bottom is 16 square feet which dimensions requie the least amount of material for the sides of the sandbox?
Ok, an important part of this is that shapes can be categorized into multiple groups. It goes something like this in this case: Quadrilateral V Rectangle V Square When dealing with shapes, regular polygons always have less perimeter than irregular for the same area. Here, a square would have a perimeter of 16, with 4x4 dimensions; the next closest rectangle would have a perimeter of 20, with dimensions of 8x2; the last rectangle you could make would have a perimeter of 34, with dimensions of 16x1.
A rectangel with the dimensions of 2 feet by 8 feet is similar to a rectangle with the dimensions of?
4 x 4 1 x 16
What happens to the perimeter of a rectangle when its length and width are quadrupled?
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
The perimeter of a rectangle is 48 feet If the length measures 16 feet what is the width?
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
