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What is the perimeter of a rectangle with a diagonal length of 7 feet and an area of 16 feet squared?
Wiki User
∙ 13y ago
The perimeter is 18 feet.
Wiki User
∙ 13y ago
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A rectangle is 4 ft by 6ft What is the length of the diagonal of the rectangle?
The diagonal is 7.21 feet.
What is a perimeter of a recangular?
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
The length of a rectangle is three times its width and the area of the rectangle is 192ft squared what is its perimeter?
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet
What is the perimeter of a rectangle that is 1.6 meters long and 0.8 meters wide?
Perimeter of rectangle = 2 x (length + width) = 2 x (1.6 + 0.8) = 2 x 2.4 = 4.8 meters
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
How do you count the number of squares crossed by the diagonal in a rectangle?
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
How do you find length with width and diagonol numbers?
Assuming you're talking about a rectangle: Diagonal squared = length squared + width squared (Pythagoras) so: Length squared = diagonal squared - width squared ie length = sqrt (diagonal squared - width squared)
How do you find diagonal of rectangle when perimeter and width are known?
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The diagonal of rectangle is citizen its grade is 37 then the perimeter is?
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
If the length of a rectangle is 3 and the width is 2 the length of the diagonal is?
a=3 b=2 c=diagonal a squared add b squared equals c squared 9 add 4 = 13 square root 13 and ther's your answer
How do you work out the diagonals of a rectangle?
Well, you know that in order to classify a shape as a rectangle all of the sides have to be congruent or 90 degrees. If you draw the diagonal of that rectangle, you come up with two right triangles. So you can use the Pythagorean theorem (a squared+b squared=c squared) to find out the diagonal. Ex: If the length=4, and width=3, then diagonal=5, because 4 squared+3 squared=5 squared.
How do you find the length of a rectangle knowing ONLY the diagonal and the width?
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
What is the equation for finding length of rectangle?
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
What is the formula to find the diagonal of a rectangle?
The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.
How do you find the unknown width of a rectangle?
It depends on what information you do have. The length and area, the length and diagonal, the length and perimeter, etc. Each set generates a different answer.
What is the diagonal length of a rectangle with an area of 532.2672 square cm and a perimeter of 932.4 mm?
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
