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There are 34650 distinct orders.There are 34650 distinct orders.There are 34650 distinct orders.There are 34650 distinct orders.
The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240
> 6.40237371 × 1015Actually, since there are four i's and two o's, the number of distinct permutations of the letters in "oversimplification" is 18!/(4!2!) = 133,382,785,536,000.
Sometimes capital letters can be mistaken for other notations used in the mathematical sciences. Lower case letters also are very distinct from one another when looking at the handwriting of different individuals.
The word "BOX" consists of 3 distinct letters. The number of arrangements of these letters can be calculated using the factorial of the number of letters, which is 3! (3 factorial). Therefore, the total number of arrangements is 3! = 3 × 2 × 1 = 6. Thus, there are 6 possible arrangements of the letters in "BOX."