For 2 it's any even number.For 5 it's if the number ends in 5 or 0.For 10 it's if the number ends with a zero. That's basically it.
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If the rules for 2 and 3 work, the number is divisibale by 5.
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
26
Those for 1, 2, 4, 5 and 8.
It is divisible by 3 and 9 but not the others.
If the rules for 2 and 3 work, the number is divisibale by 5.
3 and 9. And they divide into 123456789 whether or not you use divisibility rules!
Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.
26
No.
Those for 1, 2, 4, 5 and 8.
You should learn to make your question clear to someone who doesn't know what you are doing. And why 895 of all numbers? If I guess what you want correctly, first you should factorize 895 = 5 * 179.. a number is divisible by 2 * 5 * 179 if and only if it is divisible by 10 and 179 separately, because 10 and 179 have no common factor. You should know the divisibility rules for 10 already. For 179, there isn't a simple test.
Divide by two and five. 1, 2, 4, 5, 10, 20
It is divisible by 3 and 9 but not the others.
If a number is divisible by 3 and 5, it is divisible by 15.
Factors are divisors. If you know the divisibility rules, you know that 80 is divisible by 1, 2, 4, 5 and 8. If you divide 80 by those numbers, you find the other half of the factor pairs.
2 : The number ends with a 2, 4, 6, 8, or zero. (The number is 'even'.)3 : The sum of the digits in the number is divisible by 3 .5 : The number ends with a zero or a 5 .6 : The number passes the tests above for both 2 and 3 .10 : The number ends with a zero.