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For 2 it's any even number.For 5 it's if the number ends in 5 or 0.For 10 it's if the number ends with a zero. That's basically it.

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14y ago

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Related Questions

What is a divisibility rule for 5?

If the rules for 2 and 3 work, the number is divisibale by 5.


What numbers 2 3 5 9 divides into 123456789 evenly using divisibility rules?

3 and 9. And they divide into 123456789 whether or not you use divisibility rules!


Can you tell if whether 432 is divisible by 2 3 4 5 6 9 10?

Yes, you can tell using the divisibility rules. The answers are yes for all but 5 and 10.


Is 85743 divisibility by 2 3 5 9 or 10?

No.


What divisibility rules determine which will divide evenly into 2 and 895?

You should learn to make your question clear to someone who doesn't know what you are doing. And why 895 of all numbers? If I guess what you want correctly, first you should factorize 895 = 5 * 179.. a number is divisible by 2 * 5 * 179 if and only if it is divisible by 10 and 179 separately, because 10 and 179 have no common factor. You should know the divisibility rules for 10 already. For 179, there isn't a simple test.


How do you use the divisibility rules to determine whether a number is divisible by 2356 or W?

To determine if a number is divisible by 2356, you can use the divisibility rules for its prime factors. First, factor 2356 into its prime components, which are 2, 4, 589. Check if the number is even (for 2), if it ends in 0 or 5 (for 5), and apply the rules for 589 as needed. For a number W, you would follow its specific divisibility rules, which may involve checking for factors or specific modular conditions.


Is 10 and 20 factors of 20?

Divide by two and five. 1, 2, 4, 5, 10, 20


What is 85743 for divisibility by 2 3 5 9 or 10?

It is divisible by 3 and 9 but not the others.


What is divisibility rules for 15?

If a number is divisible by 3 and 5, it is divisible by 15.


What does it means to use the divisibility rules to find factor pairs for eighty?

Factors are divisors. If you know the divisibility rules, you know that 80 is divisible by 1, 2, 4, 5 and 8. If you divide 80 by those numbers, you find the other half of the factor pairs.


What are the divisibility rules for 2 3 5 6 and 10?

2 : The number ends with a 2, 4, 6, 8, or zero. (The number is 'even'.)3 : The sum of the digits in the number is divisible by 3 .5 : The number ends with a zero or a 5 .6 : The number passes the tests above for both 2 and 3 .10 : The number ends with a zero.


How divisibility rules can help you find the prime factorization?

Suppose you were trying to find the prime factorization of 123. You know that half of the divisors will be less than the square root. Since the square root is between 11 and 12, you only need to test 2, 3, 5, 7 and 11 as prime factors. If you know the rules of divisibility, you already know that 2 and 5 aren't factors and 3 is. It saves time.