If the number is even, it's divisible by 2.
If the sum of the digits is a multiple of 3, the whole number is divisible by 3.
If the last two digits are a multiple of 4, the whole number is divisible by 4.
If the last digit is a 0 or a 5, the whole number is divisible by 5.
If the number is even and divisible by 3, it's divisible by 6.
If the sum of the digits is a multiple of 9, the whole number is divisible by 9.
If the number ends in 0, it's divisible by 10.
To determine if 28751 is divisible by these numbers, we can check the divisibility rules. It is not divisible by 2 (as it is odd) or by 5 (since it does not end in 0 or 5). For 3, we sum the digits (2 + 8 + 7 + 5 + 1 = 23), which is not divisible by 3. Similarly, for 9, since 23 is not divisible by 9, 28751 is also not divisible by 9 or 10. Thus, 28751 is not divisible by 2, 3, 5, 9, or 10.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
It is evenly divisible by 2 and by 3.
To determine if 28751 is divisible by these numbers, we can check the divisibility rules. It is not divisible by 2 (as it is odd) or by 5 (since it does not end in 0 or 5). For 3, we sum the digits (2 + 8 + 7 + 5 + 1 = 23), which is not divisible by 3. Similarly, for 9, since 23 is not divisible by 9, 28751 is also not divisible by 9 or 10. Thus, 28751 is not divisible by 2, 3, 5, 9, or 10.
It is divisible by 2 and 3. It isn't divisible by 5 and 10.
Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.
It is evenly divisible by 2 and 10 but not by 3 and 9.
9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.
20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.
It is divisible by 2, 5 and 10, but not 3 and 9.
To determine what 70320 is divisible by, we need to consider the divisibility rules for common numbers. 70320 is divisible by 2 because it ends in 0, by 3 because the sum of its digits (7+0+3+2+0) is 12 which is divisible by 3, by 4 because the last two digits (20) form a number divisible by 4, and by 5 because it ends in 0. It is not divisible by 6 because it is not divisible by both 2 and 3, and not by 7, 8, 9, or 10 based on the given rules.
It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10
No since only numbers in which its sum can be divisible by 3 is divisible by 3. 2 + 4 + 4 is 10, and 10 is not divisible by 3.
29,178 is divisible by 2, 3 and 9, not by 5 or 10.
It is evenly divisible by 2 and by 3.