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276 = 2^2*3*23

So the divisors of 276 are 2^a*3^b*23^c where 0<=a<=2, 0<=b<=1 and 0<=c<=1.

That is,

1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138 and 276.

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9y ago
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Q: What are the divisors of 276?
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