The divisors of 101 are: 1, 101.
2,835 has 20 divisors.
120,000 has 70 proper divisors.
Since 11 is a prime number, its only divisors are 1 and itself.
They are: 1, 2, 4, 7, 8, 14, 28, 56.
276 = 2^2*3*23 So the divisors of 276 are 2^a*3^b*23^c where 0<=a<=2, 0<=b<=1 and 0<=c<=1. That is, 1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138 and 276.
The divisors of 39 are 1, 3, 13, and 39
All multiples of 276, which is an infinite number.
99 has six divisors: 1, 3, 9, 11, 33, 99.
138*2=276 92*3= 276 69*4=276 Those are all the whole numbers can be multiplied by...
22 has four divisors (also called factors): 1, 2, 11, 22.
its 217
60
1 and 29.
These are all the divisors of 64: 1, 2, 4, 8, 16, 32, 64.
The divisors of 40: 1 | 2 | 4 | 5 | 8 | 10 | 20 | 40 (8 divisors)
1,815