1, 2, 4, 8, 16, 31, 62, 124, 248, and 496
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The factors of 496 (excluding itself) are: 1, 2, 4, 8, 16, 31, 62, 124, 248 whose sum is 496. -------------------------------------------- The prime factorization of 496 is 496 = 24*31. If we take σ(496) (sum of all divisors of 496), this is equal to σ(496) = σ(24)σ(31) (this is a useful property, σ(ab) = σ(a)σ(b) for relatively prime a,b) Since σ(24) = 1+2+4+8+16 = 31 and σ(31) = 1+31 = 32, σ(496) = 31*32 = 2(496), so 496 is perfect.
49600%496= 496 * 100%= 49600%
The divisors of 66 are 1,2,3,6,11,22,33 and 66.
The divisors of 79 are: 1, 79.
The divisors of 23 are: 1, 23.