x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
It has no solutions because the discriminant of the quadratic equation is less than zero.
Factors (x - 7)(x + 2) so x = 7 or -2.
If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
2x+1=5x
Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
Did you get the question from sevenstar academy, Algebra.
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
It has no solutions because the discriminant of the quadratic equation is less than zero.
Factors (x - 7)(x + 2) so x = 7 or -2.
If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4
x2-5x-36 = (x-9(x+4) when factored
x=8
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2-5x+4 = (x-1)(x-4) when factord