(x+3)(x-4)
x2-5x-36 = (x-9(x+4) when factored
(x + 3)(x + 4)
x3+x2+x First, factor out the x: x(x2+x+1) Could stop there, but the rest is factor-able using imaginary numbers: x(x+.5(1+i(3).5)(x+.5(1-i(3).5), where i = (-1).5, or sqrt(-1)
x2 + 6x - 2 can not be factored
-3
L2 math.
x2-2x-15 = (x+3)(x-5) when factored
(x + 6)(x - 6)
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
(x+3)(x-4)
(x + y)(x - y) = 16
x2-5x-36 = (x-9(x+4) when factored
y = x2 - 4x + 4 can be factored into y = (x-2)(x-2) The repeated factor is 2.
(x - 3)(x - 2)
x2-5x+4 = (x-1)(x-4) when factord
You don't factor an equation. You factor an expression.So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".x2 + 5x + 6 = (x + 3) (x + 2).Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.