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3 numbers whose product is about 9000 estimate?
As a product of its prime factors in exponents: 23*32*53 = 9000
What Equals 9000?
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
How do you prime factorize the sum 9000?
9000 is an even number, it ends in '2'. Since '2' is a prime number , divide by ;2; Hence 9000 / 2 = 4500 Divide by '2' again and continue 4500/2 = 2250 2250/2 = 1125 Since '1125' ends in '5' it will divide by '5' , a prime number. 1125/5 = 225 225/5 = 45 45/5 = 9 9 /3 = 3 3/3 = 1 So the prime factors are 2,3,& 5. Fully 2^(3) X 5^(3) X 3^(2) = 9000
What are the factors and prime factors of 233357?
The factors of 233357 are: 1 233357 The prime factors are: (233357 is a prime number)
What is example of prime factor?
All numbers have factors. Some factors are prime numbers. These are known as prime factors. 2 and 3 are prime factors of 6. 1 and 6 are not prime factors of 6.
