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9000 is an even number, it ends in '2'.

Since '2' is a Prime number , divide by ;2;

Hence

9000 / 2 = 4500

Divide by '2' again and continue

4500/2 = 2250

2250/2 = 1125

Since '1125' ends in '5' it will divide by '5' , a prime number.

1125/5 = 225

225/5 = 45

45/5 = 9

9 /3 = 3

3/3 = 1

So the prime factors are 2,3,& 5.

Fully 2^(3) X 5^(3) X 3^(2) = 9000

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lenpollock

Lvl 16
1y ago

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23 x 32 x 53 = 9000

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Wiki User

10y ago
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Q: How do you prime factorize the sum 9000?
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