9000 is an even number, it ends in '2'.
Since '2' is a Prime number , divide by ;2;
Hence
9000 / 2 = 4500
Divide by '2' again and continue
4500/2 = 2250
2250/2 = 1125
Since '1125' ends in '5' it will divide by '5' , a prime number.
1125/5 = 225
225/5 = 45
45/5 = 9
9 /3 = 3
3/3 = 1
So the prime factors are 2,3,& 5.
Fully 2^(3) X 5^(3) X 3^(2) = 9000
Prime numbers don't factorize; they're already prime.
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
You can use prime numbers to factorize numbers, a very useful tool
what prime numbers have the sum of 54
The prime factorizationof 99 is 3 x 3 x 11.
Prime numbers don't factorize; they're already prime.
3 times 5
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
180 x (52-2) = 9000 The sum of the interior angles is 9000 degrees.
You can use prime numbers to factorize numbers, a very useful tool
break it into prime number multiples,10 = 2 * 5 (both prime numbers)example: factorize 387(387) = 9 * 43 (both primes , end of excercise)factorize 390:(390) = 2 * (195) = 3 * (65) = 5 * 13 (both primes , end of excercise)
You can use prime numbers to factorize numbers, a very useful tool.
9000 = 23 x 32 x 53
A polygon with n sides inscribed in a circle has an angle sum of 180xn-360 So the problem is find n so that 180n-360=9000 => n=48 The regular polygon with an angle sum of 9000 has 48 sides
2 x 2 x 3 x 19 = 228
The prime factorizationof 99 is 3 x 3 x 11.
what prime numbers have the sum of 54