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What are the prime factors of 720 using exponents?
24 x 32 x 5 = 720
How the you get the multiplication maze of 720?
As a product of its prime factors: 2*2*2*2*3*3*5 = 720 or as 24*32*5 = 720
What do all 16 12 9 and 10 all go into?
This is a "least common multiple (LCM)" question in disguise. The prime factors of 16 are 2, 2, 2 and 2 The prime factors of 12 are 2, 2, and 3 The prime factors of 9 are 3 and 3 The prime factors of 10 are 2 and 5 So, the least common multiple (and any multiple) will have to have factors of * four 2s * two 3s * one 5 (2 x 2 x 2 x 2) x (3 x 3) x 5 = 16 x 9 x 5 = 720 To prove our findings * 720 ÷ 16 = 45 * 720 ÷ 12 = 60 * 720 ÷ 9 = 80 * 720 ÷ 10 = 72 These numbers will also evenly divide into any multiple of 720, such as 1,440, 2,160, 2,880 etc.
What is the product of prime numbers for the number 720?
The prime factorization of 720 is 2x2x2x2x3x3x5 or 24x32x5.
What is the next prime number after 720?
727
