This is a "least common multiple (LCM)" question in disguise.
The prime factors of 16 are 2, 2, 2 and 2
The prime factors of 12 are 2, 2, and 3
The prime factors of 9 are 3 and 3
The prime factors of 10 are 2 and 5
So, the least common multiple (and any multiple) will have to have factors of
* four 2s * two 3s * one 5
(2 x 2 x 2 x 2) x (3 x 3) x 5 = 16 x 9 x 5 = 720
To prove our findings
* 720 ÷ 16 = 45 * 720 ÷ 12 = 60 * 720 ÷ 9 = 80 * 720 ÷ 10 = 72
These numbers will also evenly divide into any multiple of 720, such as 1,440, 2,160, 2,880 etc.
The first number that 12 and 16 go into is 48.
2 8/2 = 4 10/2 = 5 12/2 = 6
3 with 10 remaining 58 - 10 = 48 = 16 + 16 + 16
60, remainder 12
12
336
they all go into 120
The first number that 12 and 16 go into is 48.
a 16 year old should go to bed no later than 12.00 oclock about 10 at night. i think about 10:30 I think about 12:00 pm.
Not as a whole number because 12/16 = 0.75
2 8/2 = 4 10/2 = 5 12/2 = 6
Well, honey, 16 can go into 28 a grand total of 1 time with a remainder of 12. It's simple math, darling. Just divide 28 by 16 and you'll see that 16 fits in there snugly once, but there's still a little leftover bit of 12 hanging around.
12 cannot go into 10 evenly. It does go in unevenly though - 10 divided by 12 is 0.8333333333333.... with the 3 repeating infinitely.
12 timesExactly 12 times
336, 672, 1008, 1344, 1680 +336 . . .
3 with 10 remaining 58 - 10 = 48 = 16 + 16 + 16
Well, honey, 12 doesn't go into 10 at all. It's like trying to fit into your high school jeans after Thanksgiving dinner - just not gonna happen. So, the answer is zero times. Math can be a real buzzkill sometimes, can't it?