What are the factors of x2-8x plus 16?

Answer 1

x^2 - 8x + 16 = 0

(x )(x )

You need two numbers that when multiplied are equal to 16, and when added are equal to 8.

These two numbers are 4 and 4 (4 * 4 = 16, 4 + 4 = 16)

Then you need to figure out if these are positive or negative. Since 16 is positive, you know that the numbers are either both positive or both negative. Since the 8 is negative, you know they must be negative.

(x - 4)*(x - 4)