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-1a
3a + 4b - 5 - 1a + 7b + 3 - 1b 2a + 10b - 5 + 3 2a + 10b - 2
a2 + 2a - 15 = 0This can be factorised:a2 + 2a - 15 = (a - 3)(a + 5) = 0So a = 3 and -5.A more robust way is to shove it into the general solution:If αx2 + βx + η = 0, then x = (-β ± √(β2 - 4αγ)) / 2αSo if a2 + 2a - 15 = 0, then:a = (-2 ± √(22 - 4*1*-15)) / 2*1a = (-2±√(64))/2 = (-2±8)/2a = -10/2, 6/2a = -5, 3
Yes. This is called the distributive property. For example: a(1 + 2 + 3 + ... + n) = 1a + 2a + 3a ... + na
a + a + a - 2a = 3a - 2a = a
since a=1a, 3a-1a=2a
1a+3b 2a+4b=3a +7b
group 1a , group 2a , transition elements , group 0 (inert gases)
Metals in group 1A, 2A, 3A can form mono-, di- and trivalent positive ions respectively, and all are metals except Boron, which is a metalloid (between Carbon -a nonmetal- and Berillium -a metal- in period II).
1
2a - a = a
-1a
el nuevo testamento contiene 27 libros y son Mateo, Marcos, Lucas, Juan, Hechos, Romanos, 1a Corintios, 2a Corintios, Gálatas, Efesios, Filipenses, Colosenses, 1a Tesalonicenses, 2a Tesalonicenses, 1a Timoteo, 2a Timoteo, Tito, Filemón, Hebreos, Santiago, 1a Pedro, 2a Pedro, 1a Juan, 2a Juan, 3a Juan, Judas y Apocalipsis o Revelación.
The GCF of 2a amd 3a is 1a. This is because 2 and 3 doesn't have a common factor so it has to be 1 and the variables a and a are the same so the answer is 1a
bilat
Tamaki is in class 2A Kyoya is in class 2A Haruhi is in class 1A Hikaru is in class 1A Kaoru is in class 1A Mori is in class 3A Hunny is in class 3A
FORTRANA-1A-2A-3COMTRANCOBOLFARGORPGetc., etc.