What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.
They are: 7, 10, 13, 16, and 19
5, 7, 9, 11 and 13
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
7
To simplify the expression (9x + 7) + (x + 3), first combine the like terms. The x terms are 9x and x, which add up to 10x. The constant terms are 7 and 3, which sum to 10. Thus, the simplified expression is 10x + 10.
They are: 7, 10, 13, 16, and 19
5, 7, 9, 11 and 13
They are 7, 10, 13, 16 and 19.
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
7
To simplify the expression (9x + 7) + (x + 3), first combine the like terms. The x terms are 9x and x, which add up to 10x. The constant terms are 7 and 3, which sum to 10. Thus, the simplified expression is 10x + 10.
Expressed as a mixed fraction in its lowest terms, 7/5 + 2 + 5/3 is equal to 5 1/15, or five and one fifteenth.
To simplify the expression ( b + 5a + 7 - 3a - 2 + 2b ), first combine like terms. The ( b ) terms are ( b + 2b = 3b ), and the ( a ) terms are ( 5a - 3a = 2a ). For the constant terms, combine ( 7 - 2 = 5 ). Thus, the simplified expression is ( 3b + 2a + 5 ).
To simplify the expression (7 + D + 8C + 4D + 2), first combine the constant terms: (7 + 2 = 9). Next, combine the like terms for (D): (D + 4D = 5D). The expression can be rewritten as (9 + 5D + 8C).
They are 7, 10, 13, 16 and 19.
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
first combine like terms and 5n+7=-41 add -7 to both sides 5n=-48 n=-48/5