7
2,1,0 is th sequence of its terms
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.
5, 7, 9, 11 and 13
All but John Adams served two terms. The total of the first five was nine terms or 36 years (almost - Washington's first term was about an month short.)
2,1,0 is th sequence of its terms
The expression "n plus 3" can be represented as ( n + 3 ). To find the first five terms, we can substitute the values ( n = 1, 2, 3, 4, ) and ( 5 ) into the expression. The first five terms are: ( 1 + 3 = 4 ) ( 2 + 3 = 5 ) ( 3 + 3 = 6 ) ( 4 + 3 = 7 ) ( 5 + 3 = 8 ) Thus, the first five terms are 4, 5, 6, 7, and 8.
no clue
What does N equal? Well to solve the problem you would do N+7x1, N+7x2, N+7x 3, N+7x4, N+7x5 to figure out the first five terms.
354, 708, 1062, 1416, 1770.
They are: 7, 10, 13, 16, and 19
5, 7, 9, 11 and 13
10,11,12,13,14 or 8,10,12,14,16
The sequence 4n + 7 represents a linear sequence where n is the position in the sequence. To find the first five terms, substitute n with 1, 2, 3, 4, and 5 respectively. Thus, the first five terms are 11, 15, 19, 23, and 27.
The first five terms of the sequence defined by (4n) can be found by substituting (n) with the integers 1 through 5. Thus, the terms are: For (n = 1): (4 \times 1 = 4) For (n = 2): (4 \times 2 = 8) For (n = 3): (4 \times 3 = 12) For (n = 4): (4 \times 4 = 16) For (n = 5): (4 \times 5 = 20) So, the first five terms are 4, 8, 12, 16, and 20.
They are 7, 10, 13, 16 and 19.