no. x is one term, and y is another term, so x+y has two terms, meaning it is a binomial
Normally, the y-intercept would be after the x term, but because there is no x term the y-intercept is 0.
The equation for a circle with radius r and centre (X, Y) is given by: (x - X)² + (y - Y)² = r² This can be expanded to give: x² - 2Xx + X² + y² - 2Yy + Y² = r² → x² - 2Xx + y² - 2Yy + X² + Y² - r² = 0 If the centre lies on the y-axis, then the x-coordinate of the centre is 0, ie the centre is at (0, Y), then -2X = 0 and the x term disappears to make the equation: x² + y² -2Yy + Y² - r² = 0 So if the centre lies on the y-axis (x = 0), then there is no term involving just x, only a term involving x².
Zero. There is no term with just y in it.
If the co-ordinate you are talking about is in the form of (X,Y) X is the term on the x axis (Bottom axis) Y is the term on the y axis (The Vertical axis) the total co-ordinate will be where the unit on each axis cross.
As a term of an expression: x-y
no. x is one term, and y is another term, so x+y has two terms, meaning it is a binomial
Normally, the y-intercept would be after the x term, but because there is no x term the y-intercept is 0.
fourth term of X-Y to the sixth power
You're re-release-did!
x is elastic to y: when y changes, x tends to change a lot with it. x is inelastic to y: when y changes, x does not change much with it.
The equation for a circle with radius r and centre (X, Y) is given by: (x - X)² + (y - Y)² = r² This can be expanded to give: x² - 2Xx + X² + y² - 2Yy + Y² = r² → x² - 2Xx + y² - 2Yy + X² + Y² - r² = 0 If the centre lies on the y-axis, then the x-coordinate of the centre is 0, ie the centre is at (0, Y), then -2X = 0 and the x term disappears to make the equation: x² + y² -2Yy + Y² - r² = 0 So if the centre lies on the y-axis (x = 0), then there is no term involving just x, only a term involving x².
y = x sin(x) + cos(x)Derivative of the first term = x cos(x) + sin(x)Derivative of the second term = -sin(x)y' = Sum of the derivatives = x cos(x) + sin(x) - sin(x)= [ x cos(x) ]
Zero. There is no term with just y in it.
char x,y,z; x=100; y=200; z=x+y; /* overflow */ x=100; y=100; z=x+y; /* overflow if signed, okay if unsigned */ x=100; y=20; z=x+y; /* okay */
If the co-ordinate you are talking about is in the form of (X,Y) X is the term on the x axis (Bottom axis) Y is the term on the y axis (The Vertical axis) the total co-ordinate will be where the unit on each axis cross.
A syllogism- apex