The equation for a circle with radius r and centre (X, Y) is given by:
(x - X)² + (y - Y)² = r²
This can be expanded to give:
x² - 2Xx + X² + y² - 2Yy + Y² = r²
→ x² - 2Xx + y² - 2Yy + X² + Y² - r² = 0
If the centre lies on the y-axis, then the x-coordinate of the centre is 0, ie the centre is at (0, Y), then -2X = 0 and the x term disappears to make the equation:
x² + y² -2Yy + Y² - r² = 0
So if the centre lies on the y-axis (x = 0), then there is no term involving just x, only a term involving x².
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The maximum and minimum points will be on the y-axis. However, I very much doubt if you could tell the difference if the centre was a microscopic distance from the axis.
Which point is not located on the xaxis or the yaxis of a coordinate grid?Read more:Which_point_is_not_located_on_the_xaxis_or_the_yaxis_of_a_coordinate_grid
The vertical y axis on the Cartesian plane is both negative and positive
.... then your graph is inverted.