They are: 3 6 9 12 15 18 ..... just add 3 each time and finally 48
36,36,39,42,45,48
3 multiples of 4 that is greater than 0 is 8,12, and 16.
12, 24, 36, 48 - the multiples of 12.
21 and 42 are.
To find the integers from 4 to 50 inclusive that are neither multiples of 3 nor 4, first determine the total count of integers in this range, which is (50 - 4 + 1 = 47). Next, calculate the multiples of 3 and 4 within this range: there are 16 multiples of 3 (from 6 to 48) and 12 multiples of 4 (from 4 to 48). Use the principle of inclusion-exclusion to account for overlaps (multiples of 12), resulting in a total of 22 integers that are multiples of either 3 or 4. Subtracting this from the total gives (47 - 22 = 25) integers that are neither multiples of 3 nor 4.
No, multiples can't be smaller than the numbers they are compared to.
No. Multiples can't be smaller than the number they are compared to.
The multiples of 3 up to 50 are: 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48
No. Multiples can't be smaller than the number they are compared to.
The first 50 multiples of 6 are the first fifty even multiples of 3.
12, 24, 36, 48
15, 30 and 45
To find the numbers between 10 and 50 that are multiples of both 3 and 5, we need to find the numbers that are multiples of the least common multiple of 3 and 5, which is 15. The multiples of 15 between 10 and 50 are 15, 30, and 45. Therefore, there are 3 numbers between 10 and 50 that are multiples of both 3 and 5.
0.06 is quite a bit smaller than 0.3 0.06 = 3/50 0.3 = 3/10 would you rather have 3 out of every 10 dollars, or only 3 out of every 50 dollars
4 and 8 are multiples of 2. 6 and 9 are multiples of 3. 40 and 50 are multiples of 10.
36,36,39,42,45,48
3, 6, 9, 12, 15, 18, 24, 27, 30, 33, 36, 39,