There are none.
The natural numbers are the counting numbers. Therefore, the natural numbers less than 31 are the numbers from 1 to 30.
The set of natural numbers less than four is {1, 2, 3}.
If you restrict yourself to natural numbers, it is 25/25 = 1/1.
That would be equal to the sum of all natural numbers less than or equal to 100 minus the sum of all natural numbers less than or equal to 89. The sum of all natural numbers less than or equal to x can be calculated with this equation: x ∑n = n(n + 1) / 2 n=1 We can take the numbers given above then, and plug them into that sum, giving us the equation: x = 100(100 + 1)/2 - 89(89 + 1) / 2 x = 5050 - 4005 x = 1045
1, 3, 5
an empty set
The odd natural numbers less than 11 are 1, 3, 5, 7, and 9.
The natural numbers are the counting numbers Thus the set m of those counting numbers less than 5 is: m = {1, 2, 3, 4}
[ 1, 2 ]
The numbers 1, 2, 3, ... , 18, 19.
1, 2, 3 & 4
infinte
1, 8,11,88,101,111,181,808,818,888,1001,1111,1881.
Natural (whole) numbers are 1,2,3, and so on.A natural number less than 7 is 1,2,3,4,5,6. Sometimes zero is included.
No - the ONLY natural number which has a reciprocal which is also a natural number is "1". All the other reciprocals of natural numbers will be fractions that are less than 1.
Yes.In general, take any natural number n. We can find n factorial by multiplying n by each natural number that is less than n. So 4! is 4x3x2x1.In the case of 1! it is just 1 since there are no natural numbers less than 1.
.75, 1, 1.5, 1.75 Unless you are only supposed to use natural numbers.