15 19
67, 131, and 259.
1 squared, 2 squared, 3 squared etc so the next 3 terms are 36,49 and 64.
multiply 3 subtract 2
If you mean: 12, 11, 9, 6, 2 then the next number is -3 Because they are being reduced by 1, 2, 3, 4 and then 5
-11
67, 131, and 259.
27 over 18 to the lowest terms is: 3 over 2 = 3/2 = 11/2 or 1.5
1 squared, 2 squared, 3 squared etc so the next 3 terms are 36,49 and 64.
18 over 12 in its lowest terms = 3/2 = 11/2 or 1.5
multiply 3 subtract 2
If you mean: 12, 11, 9, 6, 2 then the next number is -3 Because they are being reduced by 1, 2, 3, 4 and then 5
-11
The numbers 2, 4, 7, 11 are neither strictly arithmetic nor geometric. In an arithmetic sequence, the difference between consecutive terms is constant, while in a geometric sequence, the ratio between consecutive terms is constant. Here, the differences between terms are 2, 3, and 4, suggesting a pattern of increasing increments. Following this pattern, the next two terms would be 16 (11 + 5) and 22 (16 + 6).
To find the missing terms in the arithmetic sequence 8, 11, 14, 17, we first identify the common difference. The difference between consecutive terms is 3 (11 - 8 = 3, 14 - 11 = 3, 17 - 14 = 3). Therefore, the terms before 8 can be calculated by subtracting 3: 5 (8 - 3) and 2 (5 - 3). The complete sequence is 2, 5, 8, 11, 14, 17.
Actually the next number in the sequence is 17 A 19 , 23 , 29 , 31 ,.......... Prim number
To factor the polynomial (x^3 + 11x^2 + 3x - 33) by grouping, first, rearrange the terms as ((x^3 + 11x^2) + (3x - 33)). Next, factor out the common terms from each group: from the first group, factor out (x^2), resulting in (x^2(x + 11)), and from the second group, factor out (3), resulting in (3(x - 11)). Now, rewrite the expression as (x^2(x + 11) + 3(x - 11)), and look for a common binomial factor to complete the factorization.
-7 -11 -15 You subtract 4 each time