4, 16, 32, 128, 512
4 x 4(1-1) = 4 x 1 = 4
4 x 4(2-1) = 4 x 4 = 16
4 x 4(3-1) = 4 x 8 = 32
4 x 4(4-1) = 4 x 32 = 128
4 x 4(5-1) = 4 x 128 = 512
Nth term=a x r(n-1), where a is first term and r is common ratio between two terms.
2and1
The next numbers in the sequence are... 16, then 88.
25 36 49 64 81 100 121 144
32
45 then 58
2and1
7^2 = 49 and 8^2 = 81
The differences between the numbers is decreasing by 8 each time. Therefore, since the difference between 48 and 32 is 16, the difference between the next two numbers will be 16 - 8 = 8. Therefore, the next number in the sequence is equal to 32 - 8 = 24.
possibly 16
The next numbers in the sequence are... 16, then 88.
25 36 49 64 81 100 121 144
32
45 then 58
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
The sequence appears to consist of numbers formed by concatenating consecutive odd numbers: 1, 4, 9, 16, 25. These numbers are the squares of the first five integers: 1², 2², 3², 4², and 5². The next number in this pattern would be 36, which is 6². Therefore, the next number in the sequence is 36.
1, 4,9, 16, 25, 36,49 this is the next three sequence po
Should there be a 16 in there somewhere? If so next three are 36, 49 and 64...