Numbers, listed in 5s and 10s, between 40 and 60 but including both numbers are:
Numbers, listed in 5s and 10s, between 40 and 60 but excluding both numbers are:
10
If you have 20 tens you have 200. You don't need the rest.
From 1-100, it appears 20 times, in 19 different numbers.5152535455051525354555657585965758595For every interval of one hundred after that (101-200, 201-300, etc.) except for 500, it will be the same amount of fives. So, 20 instances times 9 different intervals (still excluding 500-599), there are 180 fives.Now we'll consider 500-599. From 0-99, there are 100 numbers, so there are also 100 numbers from 500-599. That means there is an extra 100 fives, for each 5 in the hundreds place. Add that to the original 20 from the tens and ones place, and there are 120 fives between 500-599.When we add that 120 on the our other 180, we arrive at the grand total of 300 fives between 1-1000.
Ten of them.
3
10
9
5/10 is greater
Five
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
If you have 20 tens you have 200. You don't need the rest.
From 1-100, it appears 20 times, in 19 different numbers.5152535455051525354555657585965758595For every interval of one hundred after that (101-200, 201-300, etc.) except for 500, it will be the same amount of fives. So, 20 instances times 9 different intervals (still excluding 500-599), there are 180 fives.Now we'll consider 500-599. From 0-99, there are 100 numbers, so there are also 100 numbers from 500-599. That means there is an extra 100 fives, for each 5 in the hundreds place. Add that to the original 20 from the tens and ones place, and there are 120 fives between 500-599.When we add that 120 on the our other 180, we arrive at the grand total of 300 fives between 1-1000.
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
Ten of them.
3
20
Well, let's see here, when we talk about numbers with 5 tens, we're looking for numbers between 50 and 59. There are 10 numbers in this range that have 5 tens. So, the answer is 10. It's a happy little math question that just wants to be solved.