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There are 41 numbers between 1 and 1,000 that are divisible by 3 and 8?
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
5
8
All numbers that are divisible by 8 and 12 would also be divisible by 4.
12. 13, if you count 200
There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.
There are 10 such numbers between 8 and 121 that are divisible by 11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110.
125 (including 1000)
Four. 24 and its multiples.
150/8 = 18.75 so 18 numbers.
All the numbers that are divisible by 8 are 1,2,and 4
There are three: 8, 16 and 24.
125 if you include 1000.
3, 5, 7. 4, 6, and 8 are divisible by 2. 9 is divisible by 3.
A number that is divisible by 4 and 6 must be divisible by the LCM of 4 and 6 which is 12. 100/12 = 8.33 200/12 = 16.67 So, there are 16 numbers below 200 that are divisible by 4 and 6 and, of these, 8 are smaller than 100. That gives 16 - 8 = 8 between 100 and 200.
Numbers divisible by 8 will all be even. They will all be divisible by 4 and again by 2, and will all be divisible by 2 and by 2 again and by 2 again.2,7,9,6,9