The probability of both dice showing the same number is 1/6 and the probability of different numbers is 5/6.
The probability is 0 since if both dice show the number 6, their sum is 12 which is not a prime.
"Dice" is both singular and plural. Usually, it's one "die" and two "dice."
It is 30/36 = 5/6
The lowest number will be obtained by getting lowest number on both of the dice if its a 6 sided dice (normal kind) then the lowest will be 2
There are 2 possible answers. If you meant is either one of the dice land on a 1, then the answer is 1/3. If you meant if they both ADD UP to 1, then it is impossible and the answer is 0. =========================================== The first answer accurately states the theoretical probabilities. But the question clearly specifies "the experimental probability". That number is the result of an experiment which, as far as we know, has not yet been perfrormed. Also, in the parlance of frequent rollers, "rolling a (x)" means a roll of two dice after which the sum of the spots showing on the top surfaces of both is (x).
Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.
There are 6 × 6 = 36 possible outcomes There are 3 odd numbers, so there are 3 × 3 = 9 results that are a success → probability of both dice showing an odd number = 9/36 = 1/4
Assuming you mean the sum of the two dice is a prime number, then: The possible outcomes are 2, 3, 5, 7, 11 which occur 1, 2, 4, 7, 2 times respectively. There are 36 possible outcomes → pr(prime_sum) = (1+2+4+7+2)/36 = 16/36 = 4/9 If you mean that both dice must show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a prime number is 3/6 = ½ → probability both show a prime number is ½ × ½ = ¼ If you mean either or both dice could show a prime number, then: The possible primes are 2, 3, 5 → probability of 1 die showing a primes is 3/6 = ½ → probability of a die not showing a prime is 1 - ½ = ½ → probability of neither die showing a prime is ½ × ½ = ¼ → probability of either or both dice show a prime is 1 - ¼ = ¾
The probability is 0 since if both dice show the number 6, their sum is 12 which is not a prime.
The probability is 0. If both dice show the number 3 then the sum is 6 which is not odd.
it depends on how many time you throw the dice. the increase number of your throw, the higher the probability to get 8 that one die is showing a 5. that what my opinion.
"Dice" is both singular and plural. Usually, it's one "die" and two "dice."
No you can decide if you want to roll one or 2 of the dice.
It is 3/36 = 1/12
Fair dice are dice that are not weighted on one side to make a particular number more probable than the others. The probablity of a four on one dice is 1/6. The probability of a four showing on either or both of two dice is 1/6 + 1/6 = 1/3 (Note this is different from rolling a total score of four with two dice which can be achieved with 1+3, 3+1 or 2+2 which is 3 out of 36 combinations or 3/36)
It is 30/36 = 5/6
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