Q: What are the odds of rolling 2 three of a kind using 6 dice in one roll?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

If it's a six-sided die (like the kind used in craps and most dice games) the odds are 1 in 6.The probability of rolling a single number on any kind of die* is 1 ÷ (the number of sides).*Except, of course, for weighted, shaved, or otherwise illegal dice.

A single roll of six dice comes up with a four of a kind 1 in every 20.736 times. This chance doesn't change on the second throw, only really granting a total of 2 in 20.736.

accumulated binominal distribution 6*f(k;n,p) = 6*f(5;5,1/6)

The probability of getting 4 of a kind with 5 dice is: 6 5C4 (1/6)4 (5/6) = 0.0192901..≈ 1.93%

The lowest number will be obtained by getting lowest number on both of the dice if its a 6 sided dice (normal kind) then the lowest will be 2

Related questions

No.

If it's a six-sided die (like the kind used in craps and most dice games) the odds are 1 in 6.The probability of rolling a single number on any kind of die* is 1 ÷ (the number of sides).*Except, of course, for weighted, shaved, or otherwise illegal dice.

The odds of rolling five of a kind with five dice is 1 in 1296. The first die is going to roll something, so the odds are 1 in 1. Each of the other dice have a probability of 1 in 6 of matching the first die, so the resultant probability is (1 in 1) times (1 in 6) to the fourth power.

That depends on what kind of dice you are rolling and how many of them you roll. If you roll two 6-sided dice once, the probability of getting the number 100 is exactly zero. You cannot get a 100 on one roll of two 6-sided dice. Other dice and different numbers of them may yield different probabilities.

A single roll of six dice comes up with a four of a kind 1 in every 20.736 times. This chance doesn't change on the second throw, only really granting a total of 2 in 20.736.

Yahtzee

accumulated binominal distribution 6*f(k;n,p) = 6*f(5;5,1/6)

If we are thinking of getting a '6', here are the odds. Wth one dice, its 1 in 6. So,with two dice its 1 in 216 with three dice its 1 in 7776 with four dice its 1 in 279936 with five dice its a huge 1 in 10077696

To compare and match values of 5 dice for a dice poker game using any generalized programming language, consider this possible algorithm... Create an array of five for each throw. Generate the throw using some kind of random number generator. Sort the array. Create another array of six, counting the number of duplicates. Sort that array by count. Compute the score for the throw, considering the ranking appropriate for the game. If you were to match the rules of poker, you would consider the ranking, in increasing value, to be high die, one pair, two pair, three of a kind, straight, full house, four of a kind, and five of a kind. Note that the flush and straight flush are not considered, because dice do not have the concept of suit. Repeat for each throw. Depending on the varient of poker you are trying to implement, add whatever logic is necessary, say to draw and replace one or more dice for draw poker. Add what ever betting and scoring system you want. Note that comparing scores of equal throw, such as two throws getting three of a kind, would require breaking the tie by considering the high die (or set) between the throws.

It would be 1/6 with 1 dice. To get 5 out of FIVE it would be 1/6 X 1/6 x 1/6 X 1/6 X 1/6 = 1/7776 odds. 4/5 would be 1/216

If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032

In the game of Yahtzee a full house is worth 25 points. A full house consists of 2 dice with the same number and three dice with the same numbers.