if you are talking about getting a roll that totals 6 - there is only one way to roll that - get all ones. as such there are 6^6 -1 = 46656 -1 = 46655 other ways to roll the dice. so the odds of not rolling a total of 6 with 6 dice is 46655/46656 = .~99.997857%. If you are talking about not rolling a 6 on ANY of the dice, there are 5 ways to roll each die that will give you something other than 6 so the number of ways to not roll any 6's is 5^6 = 15625. That means the odds of not rolling any 6's on 6 dice is 15625/46656 = ~38.489798%
-4
The possibilities are 2, 4 and 6 which are all multiples of two. So the odds are 50:50
Approximately 1/1120 * You have a 27.777% chance of rolling either a six or an eight on the first roll. * You have a 13.888% chance of rolling the same thing as the first roll. * You have a 13.888% chance of doing it again. * You have a 16.666% chance of rolling a seven. To find total probability in this situation, you multiply all of your chances together. .27777 x .13888 x .13888 x .16666 = 0.000892886 = .0892886% =1/1119.964 You may just be finding this out now, but casinos have known it for a long time. The casinos simply make their payouts less than the probability and they can't lose. While I recognize that your question deals with the probablity of an event recurring, for the average gambler, there is another way to look at this. Dice have no memory. Therefore, each time you roll them, the probability of rolling a given number remains the same. Each time you roll the dice, the chances of rolling a 6 before a 7 is 6 to 5 against you. The same odds apply to rolling an 8 before a 7.
If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.
if you are talking about getting a roll that totals 6 - there is only one way to roll that - get all ones. as such there are 6^6 -1 = 46656 -1 = 46655 other ways to roll the dice. so the odds of not rolling a total of 6 with 6 dice is 46655/46656 = .~99.997857%. If you are talking about not rolling a 6 on ANY of the dice, there are 5 ways to roll each die that will give you something other than 6 so the number of ways to not roll any 6's is 5^6 = 15625. That means the odds of not rolling any 6's on 6 dice is 15625/46656 = ~38.489798%
-4
The possibilities are 2, 4 and 6 which are all multiples of two. So the odds are 50:50
The sample space for 1 roll is of size 6.
6 outcomes each roll, 3 rolls. 6*6*6 = 216.
Approximately 1/1120 * You have a 27.777% chance of rolling either a six or an eight on the first roll. * You have a 13.888% chance of rolling the same thing as the first roll. * You have a 13.888% chance of doing it again. * You have a 16.666% chance of rolling a seven. To find total probability in this situation, you multiply all of your chances together. .27777 x .13888 x .13888 x .16666 = 0.000892886 = .0892886% =1/1119.964 You may just be finding this out now, but casinos have known it for a long time. The casinos simply make their payouts less than the probability and they can't lose. While I recognize that your question deals with the probablity of an event recurring, for the average gambler, there is another way to look at this. Dice have no memory. Therefore, each time you roll them, the probability of rolling a given number remains the same. Each time you roll the dice, the chances of rolling a 6 before a 7 is 6 to 5 against you. The same odds apply to rolling an 8 before a 7.
The probability of rolling the same number on five dice is (1/6)4, or about 0.0007716.
The probability or rolling a 7 with one roll of a pair (2) dice is 0.166666.... We get this number by dividing 6 by 36 (or 1 by 6). Let's review what a probability is and then find out how we get the 6 and the 36.We know that probabilities range from zero (0) to one (1), inclusive. A probability of 0 means that a given result cannot happen. Like rolling a 13 with one toss of a pair of dice. The largest number that can appear is 12, so rolling a 13 cannot be done. The probability of that happening is 0.A probability of 1 means it must happen. Like rolling a number between 2 and 12, inclusive, with one roll of the dice. Rolling a 2, 3, 4, 5, 6 7, 8, 9, 10, 11, or 12, is something that must happen, so the probability of that is 1. All probabilities that something will happen will fall on or between 0 and 1. All of them. Some folks often interchange the term probability with "the odds" of something happening, and this might be the cause of some confusion. Now that we've reviewed probability, let's look at odds and see where the numbers come from.There are 6 ways to make a 7 with two dice. They are 1-6, 2-5, 3-4, 4-3, 5-2, and 6-1. And there are 36 (6 x 6) possible outcomes with a single roll of two dice. The odds of a 7 coming up are 6 in 36, or 1 in 6. As this is true, the probability of the 7 appearing will be the number of times the combination is possible (6) divided by the total possible combinations (36), which leads us to 6 divided by 36 or 1 divided by 6, or 0.166666....Use the link to the Related question to see about the odds of rolling that 7 with two dice.
i think you roll all 10 of these dice at once and it is similar to farkle
If we roll 2 dice simultanosly the sample space consists of 6 rows and 6 col so the answer is 6*6 i.e 36 elements.If we roll 6 dice simultanosly the sample space consists of 36 rows and 36 col so the answer is 36*36 i.e 1296 elements.
The probability of rolling a number greater than 8 on one roll of a pair of dice is 0.277777.... Let's see how we get that probability, and, though it may be a little long winded, it's important to understand what's going on.With one roll of a pair of dice, we have 36 possible outcomes. They are 1-1, 1-2, 1-3,..., 6-4, 6-5, 6-6. To roll a number greater than 8, we have to roll a 9, 10, 11, or 12. There are 10 ways to roll one of those numbers. We could see 3-6, 4-5, 5-4, or 6-3 (to make 9), or 4-6, 5-5, or 6-4 (to make 10), or 5-6 or 6-5 (to make 11), or 6-6 to make 12. That's a total of 10 probable outcomes yielding a number greater than 8. As there are 36 possible outcomes, and 10 yield our required number, the odds of rolling a number greater than 8 are 10 in 36, or 5 in 18 (which is 10 divided by 36 reduced). To discover the probability of a number greater than 8, we need to divide the 10 by 36, and this gives us 0.277777.... as that probability.Note that the question asked for the probability of the given event, and not the odds. Probability is different from "the odds" of something happening when we consider the mathematics, and the two must be distunguished. We note that the odds "appear" when we calculte probability, but the two are different. There is one more idea.The probability of something happening is a number that is the ratio of the number of times that a given outcome will appear divided by the number of all possible outcomes. With dice, the number of all the combinations that can come up is 36. That means the probability of rolling any number is the number of times that the number can come up divided by all the possble combinations, or that 36.All probabilities range between zero (0) and one (1), inclusive. If something cannot happen, the probability of it happening is zero. Like rolling a 13 with one roll of the dice. If the probability of something happening, it will happen. Like rolling an odd or an even number with one roll of the dice. All the possible combinations are odd or even, so the probability of rolling an odd or an even number is one. You will get one or the other.
AnswerThe most likely number is seven.This can be 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.Remember that dice have no memory - if you have rolled 7 three times in a row the odds of rolling another 7 does not change.this is all wrong don't listen that